UVA 1546 - Complete the sequence!

题意：给定多项式前s项，求出后c项，要求尽量小

思路：利用差分法，对原序列求s - 1次差分，就能够发现规律，然后对于每多一项，就逆推回去就可以

代码：

#include 
     
      #include 
      
       const int N = 205;int t, s, c, a[N][N];int main() {    scanf("%d", &t);    while (t--) {	scanf("%d%d", &s, &c);	memset(a, 0, sizeof(a));	for (int i = 0; i < s; i++)	    scanf("%d", &a[0][i]);	for (int i = 1; i < s; i++)	    for (int j = 0; j < s - i; j++)		a[i][j] = a[i - 1][j + 1] - a[i - 1][j];	for (int i = 0; i < c; i++) {	    for (int j = s - 1; j >= 0; j--)		a[j][s - j + i] = a[j + 1][s - j - 1 + i] + a[j][s - j - 1 + i];	    printf("%d%c", a[0][s + i], (i == c - 1 ? '\n' : ' '));	}    }    return 0;}